Find the point of intersection of the pair of straight lines.10x - 4y = 43-3x - 3y = -15(x, y) = ( , )

Answer:(x,y) = ([tex]\frac{9}{2}[/tex],[tex]\frac{1}{2}[/tex])Step-by-step explanation:We have to find point of intersection of two lines.the given equations of line are:10x - 4y = 43 - (1)-3x - 3y = -15 - (2)Multiplying the first equation by 3 we have:(10x - 4y = 43)×3 = 30x - 12 y = 129 - (3)Multiplying second equation by 10 we have :(-3x - 3y = -15)×10 = -30x -30y = -150 - (4)Now, adding equation (3) and (4)  we have:-42y = -21⇒ y = [tex]\frac{1}{2}[/tex]Now, putting this value of y in equation (1), we have 10x - 2 = 43⇒ 10x = 45⇒x = [tex]\frac{9}{2}[/tex]Hence, the intersection of given two lines is (x,y) = ([tex]\frac{9}{2}[/tex],[tex]\frac{1}{2}[/tex])