The vertex of this parabola is at (-3,2) Which of the following could be its equation A. Y=4(x-3)^2+2 B. Y=4(x+3)^2-2C. Y=4(x-3)^2-2D. Y=4(x+3)^2+2
Accepted Solution
A:
Answer:DStep-by-step explanation:Vertex form is y=a(x-h)^2+k where (h,k) is vertexSo replace h with -3 and k with 2 Β y=a(x--3)^2+2y=a(x+3)^2+2So the only choice it could be is D