MATH SOLVE

3 months ago

Q:
# Use the quadratic formula to solve the equation. 2x2β6x+1=0 Enter your answers, in simplified radical form, in the boxes.

Accepted Solution

A:

X= -b +- square root of b^2-4ac

ββββββ-

2a

6 +- square root of 36-4(2)(1)

βββ

4

6+- square root of 32

βββ

4

6+- 4 square root of 2

βββ

4

3 +- 2 square root of 2

βββ

2

ββββββ-

2a

6 +- square root of 36-4(2)(1)

βββ

4

6+- square root of 32

βββ

4

6+- 4 square root of 2

βββ

4

3 +- 2 square root of 2

βββ

2